10x^2-104x+236=0

Solution for 10x^2-104x+236=0 equation:

10x^2-104x+236=0

a = 10; b = -104; c = +236;
Δ = b2-4ac
Δ = -1042-4·10·236
Δ = 1376
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1376}=\sqrt{16*86}=\sqrt{16}*\sqrt{86}=4\sqrt{86}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-4\sqrt{86}}{2*10}=\frac{104-4\sqrt{86}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+4\sqrt{86}}{2*10}=\frac{104+4\sqrt{86}}{20}
$